[OPEN-ILS-DEV] PATCH: osrf_json_object.c (miscellaneous)
Scott McKellar
mck9 at swbell.net
Sun Dec 9 01:10:53 EST 2007
There are two similar memory leaks in osrf_json_object.c, at lines 640
and 669. In each case we pass the return value of jsonObjectClone()
to osrfAppRespond(), and never free the clone.
We could capture the clone pointers and then free them. However it
would be both simpler and more efficient just to eliminate the layer
of cloning by passing the original jsonObject* directly. Thus, for
example:
osrfAppRespond( ctx, jsonObjectClone(cur->item) );
...becomes:
osrfAppRespond( ctx, cur->item );
Scott McKellar
http://home.swbell.net/mck9/ct/
--- Scott McKellar <mck9 at swbell.net> wrote:
>
> --- Mike Rylander <mrylander at gmail.com> wrote:
>
> > The other part that I'm not positive about, but I believe to be
> true
> > (and coded for), is that osrfAppRespond() takes care of destroying
> > the object it is passed. Basically, I'm not freeing anything that
> > comes out of the ctx object (hash, and all its descendants), nor
> > anything I return to the client.
>
> If you are referring to the second parameter of osrfAppRespond(),
> which is a const jsonObject*, the answer is no -- that object doesn't
> get freed. In fact osrfAppRespond can't free it, at least not
> without
> a loathsome cast, because of the constness.
>
> So I think this is indeed a leak. We call osrfAppRespond in line
> 2433:
>
> osrfAppRespond( ctx, oilsMakeJSONFromResult( result ) );
>
> The second parameter is a newly allocated jsonObject created by
> oilsMakeJSONFromResult(). That object never gets freed. We need to
> capture the pointer in a variable, pass the variable as a parameter,
> and then free it via jsonObjectFree():
>
> jsonObject * resultObj = oilsMakeJSONFromResult( result );
> osrfAppRespond( ctx, resultObj ):
> jsonObjectFree( resultObj );
>
> Scott McKellar
> http://home.swbell.net/mck9/ct/
>
>
>
>
>
>
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